Pre-Calculus for Programmers

Fractions, conjugates and rearranging

Pre-Calculus for Programmers

Fractions, conjugates and rearranging

Hard0 of 21 parts

These are the parts of the section that calculus uses most heavily, and they are the ones worth over-practising. Several of them are exactly the manipulation a derivative asks for, with the calculus removed.

1

Simplify x2−9x2−x−6\dfrac{x^{2}-9}{x^{2}-x-6}.

in terms of x

2

Write 2x+1+3x−2\dfrac{2}{x+1} + \dfrac{3}{x-2} as a single fraction.

in terms of x

3

Simplify the complex fraction 1x−13x−3\dfrac{\frac{1}{x}-\frac{1}{3}}{x-3}.

in terms of x

4

Rationalise the numerator of x+4−2x\dfrac{\sqrt{x+4}-2}{x}.

in terms of x

5

Rationalise the numerator of x−7x−7\dfrac{\sqrt{x}-\sqrt{7}}{x-7}.

in terms of x

6

Write x1/2+x−1/2x^{1/2}+x^{-1/2} as a single fraction.

in terms of x

7

Write 2x(x+3)−1/2+(x+3)1/22x(x+3)^{-1/2} + (x+3)^{1/2} as a single fraction.

in terms of x

8

Writing x2+10x+7x^{2}+10x+7 in the form (x+p)2+q(x+p)^{2}+q, what is qq?

9

Writing 2x2−12x+52x^{2}-12x+5 in the form 2(x−h)2+k2(x-h)^{2}+k, what is kk?

10

Solve A=P(1+rt)A = P(1+rt) for rr.

in terms of A, P, t

11

Simplify x2−1x2+4x+3⋅x+3x\dfrac{x^{2}-1}{x^{2}+4x+3}\cdot\dfrac{x+3}{x}.

in terms of x

12

Simplify x2−4x2+6x+9÷x−2x+3\dfrac{x^{2}-4}{x^{2}+6x+9} \div \dfrac{x-2}{x+3}.

in terms of x

13

Simplify x2−x−6x2−4⋅x+2x−3\dfrac{x^{2}-x-6}{x^{2}-4}\cdot\dfrac{x+2}{x-3}.

in terms of x

14

Rationalise the denominator of 3x−2\dfrac{3}{\sqrt{x}-\sqrt{2}}, for x>2x > 2.

in terms of x

15

Rationalise the numerator of x+h−xh\dfrac{\sqrt{x+h}-\sqrt{x}}{h}.

in terms of x, h

16

Write x−3/2+x−1/2x^{-3/2}+x^{-1/2} as a single fraction.

in terms of x

17

Write x2+7x+3x^{2}+7x+3 in the form (x+p)2+q(x+p)^{2}+q.

in terms of x

18

Write x2−3x−5x^{2}-3x-5 in the form (x+p)2+q(x+p)^{2}+q.

in terms of x

19

Write 2x2+10x+32x^{2}+10x+3 in the form a(x+p)2+qa(x+p)^{2}+q.

in terms of x

20

Solve 1c=1a+1b\dfrac{1}{c} = \dfrac{1}{a}+\dfrac{1}{b} for aa.

in terms of b, c

21

Solve v2=u2+2asv^{2} = u^{2}+2as for aa.

in terms of v, u, s